what is out put of the following code?
#include
class Base
{
Base()
{
cout<<"constructor base";
}
~Base()
{
cout<<"destructor base";
}
}
class Derived:public Base
{
Derived()
{
cout<<"constructor derived";
}
~Derived()
{
cout<<"destructor derived";
}
}
void main()
{
Base *var=new Derived();
delete var;
}
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Answer / pooja sonawane
error.
because, there is no header file.
and no ";" is given after the end of classes.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / kapil
There are 3 errors mainly
first header files are not included
second no semicolon at the end of class
third constructor of class cannot be private
if all these three errors are removed the output will be
constructor base
constructor derived
destructor base
| Is This Answer Correct ? | 1 Yes | 0 No |
why we are using semicolon at the end of printh statment
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