For testing 33kv cable hipot testing. How much kv we have to
Apply .Give in details.
Answers were Sorted based on User's Feedback
Answer / zahid ali
2E + 1 KV = 67 KV DC Hi pot
67 * .707 = 47 KV AC Hi pot
Is This Answer Correct ? | 119 Yes | 57 No |
Answer / bapi
AS HI POT TEST IS CONDUCTED IN DC SO APPROX. 1.5 TIMES OF
AC SUPPLY VOLTAGE IS APPLIED FOR 1 MINUTE.
FOR 33 kV CABLE APPROX. 50kV FOR 1 MINUTE WILL BE APPLIED.
FOR TESTING OF "R" PHASE WE HAVE TO SHORT "Y" AND "B" PHASE
ALONG WITH ARMOUR & IT SHOULD BE EARTHED. SIMILARLY FOR Y &
B PHASE.
AFTER EACH PHASE TESTING IT SHOULD BE DISCHARGED THROUGH
DISCHARGE RODS.
Is This Answer Correct ? | 65 Yes | 30 No |
Answer / s.jeganath
(2E+1)1.414=dc
2E+1 =AC
(2*33000+1)1.414=DC
67000*1.414=DC
94738v=DC (it is a 100%)
but apply in 80% only it is standard for 33kv cable
APPly voltage dc=94738*0.8=75790V
(75.790KV DC)
Is This Answer Correct ? | 42 Yes | 18 No |
Answer / mathiraja
2E+1KV=67KV FOR AC VOLTS
(2E+1KV)*1.414=94.73KV FOR DC VOLTS
ACCORDING TO IEC60950 STANDARDS.
Is This Answer Correct ? | 21 Yes | 2 No |
Answer / manikandan n
For DC Hipot test the applied voltage calculating formula is equal to (2E+1000)*1.414*(80/100)
E = system voltage
1.414 = For DC RMS conversion.
80% = test conduct in site at second time.
Is This Answer Correct ? | 17 Yes | 4 No |
Answer / ram sundar
For DC HIPOT = 1.414*(2E+1)
E=33/1.73=19.07
DC Hipot = 1.414*(2*19.07+1)
55.34kv approx 56Kv
Is This Answer Correct ? | 8 Yes | 0 No |
Answer / sunil choudhary
FOR TESTING 6.6KV CABLE HIPOT TESTING.HOW MUCH KV WE HAVE
TO
APPLY .GIVE IN DETAILS.
sunil choudhary
Is This Answer Correct ? | 20 Yes | 15 No |
Answer / yousaf
D.C. voltage equal to 3 x U0 shall be applied for 15 minutes. The standard is 1EC5840.
57KV FOR 15 MIN.
Is This Answer Correct ? | 9 Yes | 5 No |
Answer / jim sreedharan
For 33 KV cables we do three tests.
1. Vlf Test: We apply 10 kv dc between graphite and armour
at a low frequency (normally between 0.02 hz to 0.05 hz)
for 1 hour.
2. Insulation Resistance :- We apply 5 kv dc for 1 min
3. High Voltage ac Test:- We apply 57.1 kv for 30 mins
(33/1.732)x 3 = 57.1 kv
God Bless
Is This Answer Correct ? | 12 Yes | 9 No |
Answer / jayasanker
33KV CABLE
FORMULA:2E+1*1.414
2*33+1*1.414 = 94KV DC
IF BUS BAR 2*33+1 = 67KV AC
Is This Answer Correct ? | 8 Yes | 5 No |
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