Answer / ashu

divide the given no by two n store the remainder in stack
and divide again by 2 to quotent the process gong on....
n store all the remainder in the same stack....
n in last pop all the element from stack n print it.

Answer / siddiqui mohd. faisal

It's very simple.
Firstly, the binary no. of 0 is 0000.
After that if you want to know the binary no. of 1 then
jaust add 1 to binary no. of 0 i.e. 0000.So, now the ans
will be 0001.But,remember here 1+1=10.So, now if you want
binary no. of 2 then add 1 to binary no. of 1 i.e. 0001.So,
the binary no. of 2 will be 0010.
I hope you got your question answer.

Answer / vaibhav

divide no. by 2 till 1 is not coming in quotient, then it
write from bottom to top

Answer / santhi perumal

#include<stdio.h>
#include<conio.h>

int main()
{
int i,number;
printf("Enter the Number\n");
scanf("%d",&number);

for(i=7;i>=0;i--)
{
if((1<<i) & number)
printf("1");
else
printf("0");
}
}

Answer / alle balraj

void main()
{
int i,n,p=0,j;
int a[10];
clrscr();
printf("Enter the value of n:\n");
scanf("%d",&n);
i=n;
while(i!=1)
{
if(n==1)
{
a[p]=1;
break;
}
if(n%2==0)
{
a[p]=n%2;
}
else
{
a[p]=n%2;
}
n=n/2;
i=n+2;
i--;
p++;
}
for(j=p;j>=0;j--)
{
printf("%d",a[j]);
}

getch();
}

Answer / bertilla

#include<conio.h>
#include<stdio.h>
void main()
{
int i,n,arr[15];
for(i=0;i<=14;i++){arr[i]=0;}
do
{
arr[i]=n%2;
n=n/2;
i--;
if(n==1){arr[i]=1;}
}while(n>1);
for(i=0;i<=15;i++)
{
printf("%d",arr[i]);
}
getch();
}

Answer / naresh m

main()
{
int a[12],n,m,i=0;
printf("enter the no to find binary no's");
scanf("%d",&n);
while(n!=0)
{
m=i++;
a[i]=n%2;
n=n/2;
}
printf("binary value is");
for(i=m;i>=0;i--)
{
printf("%d",a[i]);
}

Answer / kk

let the number be n
int bin(int n)
{
static int sum=0;

if(n>1)
{
rem=n%2;
sum = sum *10 +rem;
n=n/2;
bin(n);
}
else
{
sum=sum*10+1;
}
return sum;
}

Answer / a.balraj

void main()
{
int i,n,p=0,temp,z;
int a[3];
clrscr();
printf("Enter the value of n:\n");
scanf("%d",&n);
i=n;
while(i!=1)
{
if(n%2==0)
{
temp=n%2;
}
else
{
temp=n%2;
}
a[p]=temp;
n=n/2;
i=n+2;
i--;
p++;
}
for(z=sizeof(a)/sizeof(int);z>=0;z--)
{
printf("%d",a[z]);
}
getch();
}

Answer / subhashini

#include<stdio.h>
#include<conio.h>
{
clrscr();
int i,sum,n;
printf("enter the number");
scanf("%d",&n);
while(n>=1)
{
i=n%2;
sum=sum*10+i;
n=n/2;
getch();
}
printf("the binary number is: %d",i)

The __________ attribute is used to announce variables based on definitions of columns in a table?

0 Answers  

Display names and numbers of employees who have 5 years or more experience and salary less than Rs.15000 using array of structures (name, number, experience and salary)

1 Answers  

what is the difference b/w compiler and debugger?

2 Answers   Assurgent,

write a programming in c to find the sum of all elements in an array through function.

0 Answers  

Magic square

0 Answers  

Explain the use of #pragma exit?

0 Answers  

What is the incorrect operator form following list(== , <> , >= , <=) and what is the reason for the answer?

0 Answers  

what is the return value (status code) of exit() function.... what the arguments(integer value) passed to it means....

1 Answers   TCS,

What is build process in c?

0 Answers  

You are to write your own versions of strcpy() and strlen (). Call them mystrcpy() and mystrlen(). Write them first as code within main(), not as functions, then, convert them to functions. You will pass two arrays to the function in the case of mystrcpy(), the source and target array.

0 Answers  

what are bit fields in c?

2 Answers  

write a program whose output will be- 1 12 123 1234

10 Answers