int i =10 main() { int i =20,n; for(n=0;n<=i;) { int i=10 i++; }

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int i =10
main()
{
int i =20,n;
for(n=0;n<=i;)
{
int i=10
i++;
}
printf("%d", i);

Question Posted / guest

6 Answers
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int i =10 main() { int i =20,n; for(n=0;n<=i;) { int i=10 i++; } printf("%d&quo..

Answer / jai

printf() will never be executed since for() is an infinite
loop.

Is This Answer Correct ?

30 Yes

2 No

int i =10 main() { int i =20,n; for(n=0;n<=i;) { int i=10 i++; } printf("%d&quo..

Answer / vikramanj

int i=10[;]
main()
{
int i=20,n;
for(n=0;n<=i;)
{
int i=10[;]
i++;
}
printf("%d", i);
The syntax errs r specified in sq.braces..
if its corrected there s no terminating condition also..
so no o/p..

Is This Answer Correct ?

8 Yes

0 No

int i =10 main() { int i =20,n; for(n=0;n<=i;) { int i=10 i++; } printf("%d&quo..

Answer / vignesh1988i

it will not print i value at all , since the loop is always
true for all cases. since the termination condition is
depending upon n&i,always n<=i, what ever possibe positive
value greater than zero ,it may be.

Is This Answer Correct ?

5 Yes

0 No

int i =10 main() { int i =20,n; for(n=0;n<=i;) { int i=10 i++; } printf("%d&quo..

Answer / dips

it doesnt have any terminating condition so it will be
infinite loop ,no output

Is This Answer Correct ?

4 Yes

0 No

int i =10 main() { int i =20,n; for(n=0;n<=i;) { int i=10 i++; } printf("%d&quo..

Answer / guest

the print would be 20.

the problem is about scope. the first i=10 is global scope.
But inside main() comes function scope. So i=20. The i
inside the for loop is of block scope and does not affect
the i outside it.

Is This Answer Correct ?

5 Yes

9 No

int i =10 main() { int i =20,n; for(n=0;n<=i;) { int i=10 i++; } printf("%d&quo..

Answer / guest

i=20

Is This Answer Correct ?

2 Yes

10 No

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