Answer / praveen kumar

let 3X be the number of bullets intially they had..
so after division each will have X bullets.
so after shooting 4 bullets .

X-4+X-4+X-4=X;
2X=12;
X=6;
so the initial number of bullets is 18

Answer / venky

18

Answer / vasanthkumarreddy

18 bullets

Answer / senthil kumar

18

Answer / bhaviya k r

let 3x be the original no of bullets. so each one will be
having x no of bullets(3x/3).since 4 bullets r being shot
4-x+4-x+4-x=x
so x=6

so answer is 6*3=18

Answer / ashish johri

let x be total no of bullets.
each had x/3.
x/3=x-4*3;
x=18;

Answer / nofiden noble

Let X be the total no. of bullets

Each of 3 shot 4 bullet...so totally 12 bullets were fired..

so,
X - 12 = X/3

on solving X=18

Answer / simkiarasu

each having x bullets
each of them shoot 4 times
total number of bullets remaining is x
so (3*4)+x=3*x
12=3x-x
12=2x
x=12/2
x=6
Answer:
each divided 6 bullets
Total no of bullets is 18.

Answer / keyur

Suppose there are 3X bullets. Each one gets X bullets..
After shot of 4 bullets. remaining bullets X - 4

(X-4)+(X-4)+(X-4)=X
so 3X-12=X
so X=6


So original bullets are 18 bullets...(3*6=18)

Answer / ashutosh

Suppose intially they had -> B bullets

After division
each had = B/3 bullets

After firing 4 bullets
each left with = (B/3 - 4)bullets

Total=3(B/3 - 4)bullets

3(B/3 - 4)= B/3 bullets


Therefore

Total Bullets =18.

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