Interested to Buy Any Domain ? << Click Here >> for more details...
void main()
{
int i=5;
printf("%d",i++ + ++i);
}
- 21 Answers
- 44584 Views
- ME, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / ravinder
Ans 12,
as addition will takes place from left to right
step1: i++ = 5;
step2: value of i will be updated before taking value of
another operand and hence i = 6;
step3: ++i = 7 as first increment will happen and then value
will be used.
final result: 5 + 7 = 12;
| Is This Answer Correct ? | 24 Yes | 8 No |
Answer / alan
when ever a cout or a printf statement is used..the instruction is processed from right to left..
had this been the qn
int i=5;
printf("%d%d",i++ + ++i,i);
ans would be 125.
as i said earlier the processing takes from right to left..
so first ++i=6,
then i++=6;
therfore 6+6=12..
| Is This Answer Correct ? | 16 Yes | 8 No |
Answer / abhijeet dongre
I HAVE PRACTICED MANY ASPECTS OF THESE QUESTIONS
THING IS THAT
PRINTING VALUES IS FROM RIGHT TO LEFT.
SOLVING AN EXPRESSION IS FROM LEFT TO RIGHT.
SOME SAMPLE OUTPUTS:-(TRY IT)
int i=5;
printf("%d",i++ + ++i); 12(5+7 only)(not 6+6)
int i=5;
printf("%d",i++ * ++i); 35(5*7 only)(not 6*6)
int i=5;
printf("%d %d",i++ + ++i,i); 12 5
int i=5;
printf("%d",i++ + i++); 11 7
printf(" %d",i);
| Is This Answer Correct ? | 8 Yes | 5 No |
Answer / nikki
its 12..
from right to left since printf executes from right to left for processing
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / vivers
There are two different questions..
in which its asking the result for
1)(i++ + ++i)
answer will be---> 12
"as addition will takes place from left to right
step1: i++ = 5;
step2: value of i will be updated before taking value of
another operand and hence i = 6;
step3: ++i = 7 as first increment will happen and then value
will be used.
final result: 5 + 7 = 12"
2) (i+++++i)
answer will be---> compile error
"because illegal combination of operators"
best of luck...
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / koushik ramesh
this program output is 12.
first is i++ is 5 only because this the post increment
first using the value after increment.
whenever i++ + the value of is 6.
++ i means this is the pre-increment.first increment
the value after using the variable this step i will become
7.
total is i++ =5
i++ + =6
++ i=7
i++ + ++i= 12. this is posted by Ramesh(MCA)Nizam
college.HYDERABAD
| Is This Answer Correct ? | 6 Yes | 5 No |
int main() { int *p=new int; *p=10; del p; cout<<*p; *p= 60; cout<<*p; } what will be the output & why?
what is c language.
Identify the operators that is not used with pointer a. && b. # c. * d. >>
the operator for exponencation is a.** b.^ c.% d.not available
What are local and global variables?
18)struct base {int a,b; base(); int virtual function1(); } struct derv1:base{ int b,c,d; derv1() int virtual function1(); } struct derv2 : base {int a,e; } base::base() { a=2;b=3; } derv1::derv1(){ b=5; c=10;d=11;} base::function1() {return(100); } derv1::function1() { return(200); } main() base ba; derv1 d1,d2; printf("%d %d",d1.a,d1.b) o/p is a)a=2;b=3; b)a=3; b=2; c)a=5; b=10; d)none 19) for the above program answer the following q's main() base da; derv1 d1; derv2 d2; printf("%d %d %d",da.function1(),d1.function1(),d2.function1 ()); o/p is a)100,200,200; b)200,100,200; c)200,200,100; d)none 20)struct { int x; int y; }abc; you can not access x by the following 1)abc-->x; 2)abc[0]-->x; abc.x; (abc)-->x; a)1,2,3 b)2&3 c)1&2 d)1,3,4
What are static functions?
What is a class?
WAP – represent a char in binary format
How many ways are there to swap two numbers without using temporary variable? Give the each logic.
What is wrong with this program statement? void = 10;
Why can't we initialise member variable of a strucutre
C 
