15 feb 2007 Reliance Paper Bangalore
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Answer / nancy
Test conducted at RNS Institute of technology, Banglaore. This is for only
B.E (Electronics & Communication Engg and Telecommunication Engg) students
Who got more than 65%.
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I wrote reliance communications limited written test on 15- feb-2007. I am
a 2006 fresher.
There were totally two sections.
Section 1 : (multiple choice questions) 75 questions 30 mins.
for this section no need to prepare any quantitative aptitude, reasoning,
verbal or non-verbal Because all the questions are different some of them
are
1)opposite of hope?
2)some proverbs given...we have to find the meaning.
3)odd man out type questions
4)some number series questions.
This section is very simple but time is important. we have to answer 75
questions in 30 mins.
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Section 2:
(Multiple choices questions) 50 questions 30 mins
For this section we have to learn the basics in Networking, OS.
They are also asked some questions in Optical communication, Laser.
Some of them are
1)LASER is a--------?
a) a coherent light
b) originated from stimulated emissions of radiation
c) ?
d) both a and b
2)bridges are in which layer?
3)some IP address is given.we have to convert?
4)some optical communication questions ?
5)routers are used to?
6)what are the two sub layers in data link layer?
7)which of the following are a FULL operating systems)
a) dos b) unix c) windows 3.1 d) OS/2
8)routers are present in which layer?
9)SONET is a ?
10) some questions in CDMA?
Number of apperared candidates: 350. They selected only..18 students
(12Boys+6G) for the second round technical.
In the second round technical they asked questions from microprocessors,
networking and digital .
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| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / guest
Hi,
Please send the Reliance placement paper for Electronics
and Instrumentation.
Thanks,
Bala
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / jitendra
hi this is jitendra need a reliance apptitude question paper
i am from electrical stream
| Is This Answer Correct ? | 1 Yes | 1 No |
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SNAPDEAL QUESTIONS 1. A train is going at a speed of 60kmph towards Delhi and returned back at a speed of 30kmph. What is its average speed? ANS : (2*30*60)/(30+60) = 40kmph 2. How many different 4 letter words can be framed that have at least one vowel? ANS : 264 - 214 (total no of 4 digits words – no of words with no vowels) 3. Write an algorithm to find out a number from an array of numbers where only one number occurs once and rest all occurs twice. ANS : XOR all the numbers ,you will get the number with single occurrences . 4. Which among the following have the product of the distance between opposite sides of a regular polygon and it side equals one fourth of the area. A. hexagon B. octagon C. n=16 D. n=18 ANS : n=16.(area of regular polygon = apothem*perimeter/2 Apothem = distance between opposite sides/2 Area = (opp_side_dist * n * a )/4 Product of opp_side_dist and side of reg. polygon = opp_side_dist * a For n= 16 the ration becomes 1:4 5. Which of the following cannot be a relation between two variables? ANS = 4th diagram. 6.what will be the output of this program Void print (int n) { If (n>0) { printf(“hello”); print(n-1); } printf(“world”); } ANS : N times hello followed by N+1 times world. 7. Which among the following cannot be used for future prediction? ANS : 4th Diagram. 8. There are 25 horses. We have to find out the fastest 3 horses In one race maximum 5 horses can run. How many such races are required in minimum to get the result. ANS : 7 races (A. first run all horses = 5 races, eliminate 4th 5th of all races. B. Run horses who came 1st in those 5 races = 1 race , the horse coming first is the fastest Run horses a. 2nd and 3rd with the fastest horse (in first time race A) b. 2nd and 3rd coming horse in B. c. The horse who came 2nd with the horse(who came 2nd in race B) in race A You will have the fastest 3 horses.) 9. In a game of rolling dice you are given 2 dice and you have to roll them. Whatever is the outcome the player will win that many dollars. What should the game owner charge each player (optimum) so that he doesn’t have to bear any loss? ANS : $7 10. We have a function REV(“string”,m,n).This function is capable of reversing the caharacters in the string from mth location to nth location. e.g. REV(“abcd”,2,3)  the output will be acbd We need to swap a string from a position,e.g. SWAP(“abcdefg”,4)  output needs to be efgabcd. How can the REV function used do this. ANS : L = string length,N= position given in SWAP function. SWAP(“abcdefg”,4) = REV(REV(REV(“abcdefg”,N+1,L),1,N),1,L).
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