Answer / raghuram.a

#include <stdio.h>
#include<conio.h>
void putlong(unsigned long x)
{
if (x>=10)
{
putlong(x/10);
}
putchar(x%10+48);
}
main()
{
unsigned long a;
clrscr();
printf("enter long integer:");
scanf("%ld",&a);
putlong(a);
getch();
return 0;

}

Answer / prateek caire

void print(unsigned n)
{
static c = 0;
if( n < 10)
{
putchar(n + 48);
return;
}
int m = n%10;
print(n/10);
if(++c%3 == 0) putchar(',');
putchar(48 + m);
}

Answer / suraj gupta

#include<stdio.h>
#include<string.h>
void printInt(unsigned long x){
int div=1;
if (x > 10){
div=x/10;
printInt(div);
}
//putchar(x % 10+'0');Both will work fine
putchar(x % 10+48);
}
int main(){
long int a;
printf(" Enter integer value : ");
scanf("%d",&a);
printf("\n");
printInt(a);
return 0;
}

Answer / sanjay

#include<stdio.h>
#include<conio.h>

int main()
{
unsigned long abc=234455787; int div1;
div1=print_int(abc);
getch();
}


int print_int(long val)
{ int div=1; char c;
if (val>=10)
{
div=print_int(val/10);
}
putchar(val%10+48);
return (1);
}

Answer / meibella

void putLong(unsigned int x, unsigned int *a, int *j)
{
unsigned int temp = x/10;
unsigned int remainder = x%10;
a[(*j)++] = remainder;
if (temp < 1)
return ;
else
putLong(temp,a,j);


}
int main()
{
unsigned int * a = new unsigned int[12] ;
int j =0;
putLong(1735648,a,&j);
for (int i = j-1; i>=0; i--)
{
putchar(a[i]+48);
}
return 0;
}

Answer / rakesh

void main()
{
unsigned long n;
int i;
void putlong(unsigned long);
cout<<"\nEnter the number::";
cin>>n;
putlong(n);
}

void putlong(unsigned long n)
{
if(n==0)
return;
print(n/10);
putchar((n%10) + 48);

}

main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

3 Answers   HCL,

#define int char main() { int i=65; printf("sizeof(i)=%d",sizeof(i)); }

1 Answers  

void main() { int i; char a[]="\0"; if(printf("%s\n",a)) printf("Ok here \n"); else printf("Forget it\n"); }

3 Answers   Accenture,

int i; main(){ int t; for ( t=4;scanf("%d",&i)-t;printf("%d\n",i)) printf("%d--",t--); } // If the inputs are 0,1,2,3 find the o/p

2 Answers  

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through testing each bit is not a solution)

7 Answers   Microsoft,

main() { int i=5,j=6,z; printf("%d",i+++j); }

2 Answers  

respected sir, i did my MCA in 2013 when i am going to attend to an interview i was asked about my project how will i explain my project could please help me in this and my project title is "Social Networking Site For Social Responsibility"

1 Answers   Genpact, Ozdocs,

what is oop?

3 Answers  

#define SQR(x) x * x main() { printf("%d", 225/SQR(15)); } a. 1 b. 225 c. 15 d. none of the above

3 Answers   HCL,

int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().

2 Answers  

Is this code legal? int *ptr; ptr = (int *) 0x400;

1 Answers  

create a C-code that will display the total fare of a passenger of a taxi if the driver press enter,the timer will stop. Every 10 counts is 2 pesos. Initial value is 25.00

0 Answers   Microsoft,