There are four dogs, each at the counter of a large square. Each of the dogs b

There are four dogs, each at the counter of a large square.
Each of the dogs begins chasing the dog clockwise from it.
All of the dogs run at the same speed. All continously
adjust their direction so that they are always heading
straight towards their clockwise neighbor. How long does it
take for the dogs to catch each other? Where does this
happen? (Hint: Dog's are moving in a symmetrical fashion,
not along the edges of the square).

Question Posted / swapna

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There are four dogs, each at the counter of a large square. Each of the dogs begins chasing the do..

Answer / manish kasera

they should meet at the center of the square.
there path converges towords the center.

Is This Answer Correct ?

14 Yes

2 No

There are four dogs, each at the counter of a large square. Each of the dogs begins chasing the do..

Answer / anirban

find the component of the initial velocity towards the
centre (V cos 45). the time taken is t= (a/sqrt(2))/ V
cos 45

Is This Answer Correct ?

7 Yes

4 No

There are four dogs, each at the counter of a large square. Each of the dogs begins chasing the do..

Answer / beshoy

This will take infinite time (because they are running from
each other with the same speed), but they are moving towards
the center of the square.
They will end up chasing in a circle that's only fit for them.

Is This Answer Correct ?

1 Yes

3 No

There are four dogs, each at the counter of a large square. Each of the dogs begins chasing the do..

Answer / asd

They never catch each other

Is This Answer Correct ?

4 Yes

7 No

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There are four dogs, each at the counter of a large square. Each of the dogs begins chasing the dog clockwise from it. All of the dogs run at the same speed. All continously adjust their direction so that they are always heading straight towards their clockwise neighbor. How long does it take for the dogs to catch each other? Where does this happen? (Hint: Dog's are moving in a symmetrical fashion, not along the edges of the square).

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