find A^B using Recursive function
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Answer / addu
#include<stdio.h>
double pow(int,int);
main()
{
int m,n;
double res;
printf("Enter the number and the power : ");
scanf("%d%d",&m,&n);
res=pow(m,n);
printf("\nThe result is = %d\n",res);
}
pow(int m,int n)
{
if(n>0)
{
return m* pow(m,n-1);
} else if (n==0){
return 1;
} else {
return (1/((double)m))*pow(m,n+1);
)
}
Is This Answer Correct ? | 5 Yes | 2 No |
Answer / nagarajanselvaraj
#include<stdio.h>
int pow(int,int);
int r=1;
main()
{
int m,n,res;
printf("Enter the number and the power : ");
scanf("%d%d",&m,&n);
res=pow(m,n);
printf("\nThe result is = %d\n",res);
}
pow(int m,int n)
{
if(n>0)
{
r=r*m;
n--;
pow(m,n);
}
return r;
}
Is This Answer Correct ? | 4 Yes | 2 No |
Question: We would like to design and implement a programming solution to the reader-writer problem using semaphores in C language under UNIX. We assume that we have three readers and two writers processes that would run concurrently. A writer is to update (write) into one memory location (let’s say a variable of type integer named temp initialized to 0). In the other hand, a reader is to read the content of temp and display its content on the screen in a formatted output. One writer can access the shared data exclusively without the presence of other writer or any reader, whereas, a reader may access the shared memory for reading with the presence of other readers (but not writers).
could you please send the program code for multiplying sparse matrix in c????
main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit >> (i - (i -1))); } } a. 512, 256, 0, 0, 0 b. 256, 256, 0, 0, 0 c. 512, 512, 512, 512, 512 d. 256, 256, 256, 256, 256
int i; main(){ int t; for ( t=4;scanf("%d",&i)-t;printf("%d\n",i)) printf("%d--",t--); } // If the inputs are 0,1,2,3 find the o/p
main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }
1 o 1 1 0 1 0 1 0 1 1 0 1 0 1 how to design this function format in c-language ?
What is full form of PEPSI
void main() { int i=i++,j=j++,k=k++; printf(“%d%d%d”,i,j,k); }
main() { int i=10,j=20; j = i, j?(i,j)?i:j:j; printf("%d %d",i,j); }
main() { 41printf("%p",main); }8
main() { int a[10]; printf("%d",*a+1-*a+3); }
What is the subtle error in the following code segment? void fun(int n, int arr[]) { int *p=0; int i=0; while(i++<n) p = &arr[i]; *p = 0; }