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#include<stdio.h>
void main()
{
int a=5,b=6,c;
int x=(a<b)+7;
int y=(x==7)*9;
int z=(c=x+y)*2;
printf("%h %h %h",x,y,z);
}
What is the output? Explain it.
- 8 Answers
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Answers were Sorted based on User's Feedback
Answer / seema choudhary
output:
x=8
y=0
z=16
x=8 because (a<b) condition is true, it return 1 means non
zero, then 1+7=8
y=0 because (x==7) condition is false return 0. then 0*9=0
z=16 because x=8,y=0 then 8+0=8*2=16
| Is This Answer Correct ? | 12 Yes | 6 No |
Answer / arun sebastin
The answer is %h %h %h
Because to print integer in c we have to use %d
but here they use %h which is wrong and the printf
statement print it without any error
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / mohit (firozabad, adc)
Here The Program will be print the Message %h%h%h only
because in the c language
the data type print the integer value by %d
character by %c
float by %f
pointer type by %u
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / moolshankershukla
erreor generate because condition will not operate directly.
such as.
int x=(a<b)+7;
int y=(x==7)*9;
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / ashish tiwari
#include<stdio.h>
void main()
{
int a=5,b=6,c;
int x=(a<b)+7;
int y=(x==7)*9;
int z=(c=x+y)*2;
printf("%d %d %d",x,y,z);
getch();
}
this is a right programme which can give out put 8 0 16..
| Is This Answer Correct ? | 0 Yes | 1 No |
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