Answer / sumitgaur2010

#include<iostream>
#include<conio.h>
#include<math.h>
using namespace std;
int main()
{
int i,n,num,p=1;
cout<<"enter the number";
cin>>n;
num=pow(2,n)+1;
for(i=2;i<num/2;i++)
{
if(num%i==0)
{
p=0;
break;
}
}
if(p==1)
cout<<"prime";
else if(p==0)
{
cout<<"factors are";
for(i=2;i<num/2;i++)
if(num%i==0)
cout<<i<<",";
}
getch();
}

Answer / ram khilawan

#include<iostream.h>
#include<conio.h>

int main()
{
int i,n,num,p=1;
cout<<"enter the number";
cin>>n;
num=pow(2,n)+1;
for(i=2;i<num/2;i++)
{
if(num%i==0)
{
p=0;
break;
}
}
if(p==1)
cout<<"prime";
else if(p==0)
{
cout<<"factors are";
for(i=2;i<num/2;i++)
if(num%i==0)
cout<<i<<",";
}
getch();
}

hello friends, given an expression we have to remove the unwanted brackets in that expression. Eg : (a+b) ---> a+b (a+b)*(c)-----> (a+b)*c. Please mail me if you know the logic. My mail id is : saravana6m@gmail.com. Thank you in advance :-)

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How to swap two ASCII numbers?

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#include<stdio.h> #include<conio.h> void main() { char str[10]; int,a,x,sw=0; clrscr(); printf("Enter a string:"); gets(str); for(x=0;x<=a;a++); for(x=0;x<=a;x++) { if(str[x]==str[a-1-x]) { sw=1; } else sw=0; } if(sw==10 printf("The entered string is palindrome:"); else printf("The entered string is not a palindrome:); } getch(); } wht would be the explanation with this written code???

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Implement a command console for changing settings on a particular object. The command console should allow you to enter a string and will return the response (very similar to a terminal session). The commands are as follows: SET propertyname=newvalue will change the target object’s member named “propertyname” to have a value equal to “newvalue”. If the input value is incompatible (i.e. an int being set to a string), print out an appropriate error message. GET propertyname will print out the current value of the target object’s member named “propertyname”. GET * will print out a list of all target object members and their current values. The system should be extensible for future commands and should accept an arbitrary object, such that another developer could insert another object into the system and rely on the command console to get and set the properties correctly.

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Deriving time complexity of Binary tree and AVL tree, step by step.

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