. Write a program using two-dimensional arrays that computes
the sum of data in tows and the sum of data in columns of
the 3x3 (three by three) array variable n[3][3].
Answers were Sorted based on User's Feedback
Answer / sreejesh1987
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,a[3][3],rowsum[3],colsum[3];
clrscr();
for(i=0;i<3;i++)
rowsum[i]=colsum[i]=0;
printf("Enter numbers:\n");
for(i=0;i<3;i++)
for(j=0;j<3;j++)
{
scanf("%d",&a[i][j]);
rowsum[i]+=a[i][j];
colsum[j]+=a[i][j];
}
for(i=0;i<3;i++)
printf("RowSum[%d]:%d\n",i,rowsum[i]);
for(i=0;i<3;i++)
printf("Columnsum[%d]:%d\n",i,colsum[i]);
getch();
}
Is This Answer Correct ? | 28 Yes | 17 No |
Answer / rowel baldemoro
#include<stdio.h>
#include <conio.h>
#include <windows.h>
#include <iostream>
using namespace std;
void design(int x, int y){
COORD coord;
coord.X=x;
coord.Y=y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE),coord);
}
int main()
{
int no[3][3],sum[2][3];
//1x3
design(1,0);
cin>>no[0][0];
design(4,0);
cin>>no[0][1];
design(7,0);
cin>>no[0][2];
sum[0][0]=no[0][0]+no[0][1]+no[0][2];
design(8,0);
printf("=%d",sum[0][0]);
//2x3
design(1,2);
cin>>no[1][0];
design(4,2);
cin>>no[1][1];
design(7,2);
cin>>no[1][2];
sum[0][1]=no[1][0]+no[1][1]+no[1][2];
design(8,2);
printf("=%d",sum[0][1]);
//3x3
design(1,4);
cin>>no[2][0];
design(4,4);
cin>>no[2][1];
design(7,4);
cin>>no[2][2];
sum[0][2]=no[2][0]+no[2][1]+no[2][2];
design(8,4);
printf("=%d",sum[0][2]);
sum[1][0]=0;
for(int i=0;i<3;i++){
design(1,6);
sum[1][0]=sum[1][0]+no[i][0];
cout<<sum[1][0];
}
design(4,6);
design(7,6);
getch();
}
Is This Answer Correct ? | 10 Yes | 4 No |
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