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) Peter and Paul are two friends. The sum of their ages is
42 years. Peter is twice as old as Paul was when Peter was
as old as Paul is now. What is the present age of Peter?
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Answer / shona
peter paul
present age X Y
whenPeter was Y Z
as old as Paul is now
(suppose before n years)
Peter(X) is twice(2) as old as Paul(Z) was when Peter(Y) was
as old as Paul(Y) is now => X=2Z
=>X-u=Y & Y-u=Z
i.e 2Z-u=Y u=Y-Z........(2)
u=2Z-y.....(1)
equating 1 & 2
2Z-Y=Y-Z
3Z=2Y
Z=2Y/3..........(3)
given
sum of their ages is 42
i.e
X+Y=42
2Z+Y=42
substituting from (3)
2*(2Y/3)+Y=42
7Y/3=42
Y=42*3/7
Y=18
so X=24
=> peter's age is 24
| Is This Answer Correct ? | 39 Yes | 4 No |
Answer / janardhana babu
PETER=X PAUL=42-X
DIFFERENCE BETWEEN TWO AGES IS (2X-42)[IF X IS GREATER THAN
42-X]
"Peter is twice as old as Paul was when Peter was
as old as Paul is now"
THIS STATEMENT SAYS THAT PRESENT AGE OF PETER=(2*PAUL) WHEN
PETER AGE =PAUL AGE...AND DIFFERENCE BETWEEN THE TWO AGES
WILL ALWAYS BE SAME WEN 'N' YEARS AGO OR HENCE..
SO EQUATION WILL BE
X = {42-X-(2X-42)}
PETER PAUL AGE WHEN peter age = paul age
AGE
by solving this equation you will get X=24(peter age)
| Is This Answer Correct ? | 11 Yes | 2 No |
Answer / jamuna
let age of peter is p and paul is pa
p+pa=42(given)--------(Eq.1)
when peter is as old as paul that is, before (p-pa) years peter's age will be:p-(p-pa)
at that time paul's age will be y-(p-pa)
it is given that(in the prblm) peter's age was twice this
there fore
p=2[p-(p-pa)]-------(Eq 2]
solving both equations 1 and 2 we get
| Is This Answer Correct ? | 7 Yes | 9 No |
Answer / mounika
peter is 25.2 paul is 16.8 when peter is 16.8 yrs, pal is
8.4 yrs... 8.4*2=16.8
| Is This Answer Correct ? | 3 Yes | 7 No |
Answer / mahesh
peter is 25 paul is 17, when peter is 17 paull is 9, 9*2=18.(approximatly correct)
| Is This Answer Correct ? | 3 Yes | 12 No |
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