OUT OF 111 MARBLES ONE IS NOT OF SAME WEIGHT. HOW TO FIND
AND GIVE THE MIN. NO OF STEPS
Answers were Sorted based on User's Feedback
Answer / sanjay kumar pal
find out the weight of a single marbles let x
then divide the 111 marbles in two groups (group1-55 and
group-2 56)
weight each group one by one. here only one group contain
the marble which has different.if weight of any group is
equal to x times the weight on no. of marble, then remove
that group.
repeat the same procedure for remaining group.
you can get the answer in min. no of steps.
Is This Answer Correct ? | 4 Yes | 2 No |
Answer / rajinikanth budigelli
stp1:- 111 devide into 3 groups.Grp A-55, Grp B-55.Grp
C-1(hold C in hand)
Case1:if weight[A]=weight[B] then ans is C.
IF NOT
Case2:then c*55= weight[A(55)] or weight[B(55)].
step2:take the group which is not equal to c*55.
Step3:repeat step1 and 2.like
Grp D[1],Grp E[27] Grp F[27].
step4:compare E[27] ,F[27].
CASE1:if E[27]=F]27] THEN ANS IS D[1].
IF NOT
CASE2:VERIFY D[1]*27 E[27] & F[27].AND PICKUP THE
GROUP WHICH IS NOT EQUAL.
STEP 5: DEVIDE THE GROUP IN TO 3 GROUPS.
G[1],H[13],I[13]RESPECTIVELY.
STEP6:REPEAT STEP(4).COMPARE H[13],I[13].
CASE1:IF H[13]=I[13].THEN ANSWER IS G[1].
ELSE
CASE2: VERIFY G[1]*13=H[13] OR G[1]*13=I[13].
PICKUP THE GROUP WHICH IS NOT EQUAL TO G[1]*13.
STEP7.AGAIN DEVIDE IT INTO 3GROUPS. J[1],K[6]L[6].
COMPARE K[6]&L[6].
CASE 1:IF K[6]=L[6] THEN ANS IS J[1].
ELSE
CASE2:PICK UP THE GROUP WHICH IS NOT EQUAL TO J[1]*6.
STEP8:HERE WE HAVE 6 MARBLES IN THE GROUP. THEN DEVIDE AGAIN
IN TO 3 GROUPS.M[2],N[2]0[2]. THEN COMPARE M,N,O.
STEP 9:HERE WE GET ONLY TWO GROPS WITH SAME WEIGHT.EXP.IF
M[2]=N[2]THEN THEY R NOT EQUAL TO O[2].
STEP 10: HERE WE GET A GROUP WITH 2 MARBLES.COMPARE O1,O2
WITH ANY OTHER REFERENCE MARBLE.HERE WE KNOW THAT O1 IS NOT
EQUAL TO O2. IF O1=REF MARBLE THEN ANS IS O2.OR IF O2=REF
MARBLE THEN ANS IS O1 MARBLE.
then hold 1 marble D[1] make 2-groups E[27],F[27] repeat
step 1,2 and 3.
step5:if E=F then ans is D. if E[27] not equal to E[27]
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / rajinikanth budigelli
stp1:- 111 devide into 3 groups.Grp A-55, Grp B-55.Grp
C-1(hold C in hand)
Case1:if weight[A]=weight[B] then ans is C.
IF NOT
Case2:then c*55= weight[A(55)] or weight[B(55)].
step2:take the group which is not equal to c*55.
Step3:repeat step1 and 2.like
Grp D[1],Grp E[27] Grp F[27].
step4:compare E[27] ,F[27].
CASE1:if E[27]=F]27] THEN ANS IS D[1].
IF NOT
CASE2:VERIFY D[1]*27 E[27] & F[27].AND PICKUP THE
GROUP WHICH IS NOT EQUAL.
STEP 5: DEVIDE THE GROUP IN TO 3 GROUPS.
G[1],H[13],I[13]RESPECTIVELY.
STEP6:REPEAT STEP(4).COMPARE H[13],I[13].
CASE1:IF H[13]=I[13].THEN ANSWER IS G[1].
ELSE
CASE2: VERIFY G[1]*13=H[13] OR G[1]*13=I[13].
PICKUP THE GROUP WHICH IS NOT EQUAL TO G[1]*13.
STEP7.AGAIN DEVIDE IT INTO 3GROUPS. J[1],K[6]L[6].
COMPARE K[6]&L[6].
CASE 1:IF K[6]=L[6] THEN ANS IS J[1].
ELSE
CASE2:PICK UP THE GROUP WHICH IS NOT EQUAL TO J[1]*6.
STEP8:HERE WE HAVE 6 MARBLES IN THE GROUP. THEN DEVIDE AGAIN
IN TO 3 GROUPS.M[2],N[2]O[2]. THEN COMPARE M,N,O.
STEP 9:HERE WE GET ONLY TWO GROPS WITH SAME WEIGHT.EXP.IF
M[2]=N[2]THEN THEY R NOT EQUAL TO O[2].
STEP 10: HERE WE GET A GROUP WITH 2 MARBLES.COMPARE O1,O2
WITH ANY OTHER REFERENCE MARBLE.HERE WE KNOW THAT O1 IS NOT
EQUAL TO O2. IF O1=REF MARBLE THEN ANS IS O2.OR IF O2=REF
MARBLE THEN ANS IS O1 MARBLE.
Is This Answer Correct ? | 0 Yes | 0 No |
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