Hi, Anybody could tell me What is the script for Reverse of
Given number. Ex:236--632. Thanks in Advance..
Answers were Sorted based on User's Feedback
Answer / deepak agrawal
int reverse=0;
while(digit)
{
reverse*=10;
reverse+=digit%10;
digit/=10;
}
Is This Answer Correct ? | 12 Yes | 2 No |
Answer / bragaadeesh
public class RevNum {
public static void main(String args[]){
int sampleNum = 12345678;
System.out.println("Input Num : "+sampleNum);
int reversedNum = 0;
while(sampleNum!=0){
reversedNum = reversedNum*10 + sampleNum%10;
sampleNum = sampleNum/10;
}
System.out.println("Reversed Num : "+reversedNum);
}
}
//SAMPLE OUTPUT
//Input Num : 12345678
//Reversed Num : 87654321
Is This Answer Correct ? | 5 Yes | 0 No |
Answer / amol zambre
str="236--678"
cnt=len(str)
for i=1 to cnt
rstr=mid(str,i,1) & rstr
next
msgbox rstr
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / rohit_allinterview
int reverse(int num)
{
int temp,num2=0;
printf("Original number is %d",num);
while(num!=0)
{
temp=num%10;
num=num/10;
num2=num2+temp;
num2=num2*10;
}
num=num2/10;
printf("Reversed Number is %d",num);
}
// Incase of any mistake or doubt plz drop mailto
rohit_vit2020@yahoo.co.in
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / anonimous
public int reverse (int num){
String b = Integer.toString(num);
char [] aa = b.toCharArray();
char []cc = new char [aa.length];
for (int m = 0; m < aa.length; m++)
cc[m] = aa[aa.length - 1 - m];
return Integer(String.valueOf(cc));
}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / parvez
'You can reverse any string with char, num and spl
characters with this code!
Sub StinrgReverse()
Dim sString, sRevString
sString = InputBox("Enter your string: ")
MsgBox sString
sRevString = fStringReverse(sString)
MsgBox sRevString
End Sub
Function fStringReverse(ByVal sBeforeRev)
Dim aStrSplit, sAfterSplit, sAfterRev, aStrRev
iLength = Len(sBeforeRev) - 1
ReDim aStrSplit(iLength) 'Very Important
For i = 0 To iLength
aStrSplit(i) = Mid(sBeforeRev, i + 1, 1)
Next
ReDim aStrRev(iLength) 'Very Important
For j = 0 To iLength
aStrRev(j) = aStrSplit(iLength - j)
Next
sAfterSplit = Join(aStrSplit, ".")
sAfterRev = Join(aStrRev, ".")
sAfterRev = Replace(sAfterRev, ".", "")
fStringReverse = sAfterRev
End Function
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / anwar basha
str="236"
for i=1 to len(str)
a=right(str,i)
temp=temp&left(a,1)
next
msgbox temp
Is This Answer Correct ? | 0 Yes | 1 No |
Answer / suryanarayan mohanty
Suppose we have number say 123
to find the revesrse of this number use
StrReverse(123).
Is This Answer Correct ? | 2 Yes | 7 No |
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