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Informatica Informatica Interview Questions
Questions Answers Views Company eMail

What is aggregate cache in aggregator transformation?

1152

What is the sql query overwrite in source qualifier in informatica

1098

Why union transformation is an active transformation?

1053

What are the limitations of joiner transformation?

1114

Explain joiner transformation in informatica

1133

What are the informatica performance improvement tips

1101

What are the mapping parameters and mapping variables?

1210

To import the flat file definition into the designer where should the flat file be placed?

1066

How are the sources and targets definitions imported in informatica designer?

1111

What are the data movement modes in informatica?

1173

How to generate or load values in to the target table based on a column value using informatica etl tool.

1083

Explain sql transformation in script mode examples in informatica

1145

What are Dimensional table?

1067

To Provide Support For Mainframes Source Data, which Files Are Used As A Source Definitions?

1116

While importing the relational source definition from the database, what are the metadata of source that will be imported?

1276

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1626


How do you change the text to fit the cell?

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In which way a two-dimensional array declared in C#?

923


Please explain the basic string operations used in c#?

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How is data represented in Spark?

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563


How will you uit the python?

940


What is the best program to wipe a hard drive?

916


I have a reference table called 1. of 2 fields called 1.BadgeGroups(BG)and 1.Badges(B)like BG G aa 10 aa 11 bb 12 bb 13 bb 14 Using MS Design View Table 2 has 3 fields called 2.name, 2.badgegroup and 2.group In Table 2 called 2. they calls Table 1 for 2 fields BUT with the second field 2.badges, I want the combo box only to display the 1.badges where 2.badgegroup = 1.badgegroup The current select I have is for Table Data View Row Source is: 2.badgegroup is filled from a Combo box using Select Distinct etc from Table 1. Tried different syntax's but still lost, looking for some help SELECT 1.[BadgeGroup], 1.Badge FROM 1. WHERE 1.[BadgeGroup]=Me.2.BadgeGroup); I can populate 2.badgegroup with a

2333


What is view explain with example?

937


Tell about the different types of banks?

1136