given the piece of code
int a[50];
int *pa;
pa=a;
to access the 6th element of the array which of the
following is incorrect?
a.*(a+5)
b.a[5]
c.pa[5]
d.*(*pa + 5)
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Answer / karthik
void main()
{
int a[50]={1,2,3,4,1,55};
int *pa;
pa=a
printf("%d",*(pa+5));
}
we will the sixth element
its not pointer to the pointer ie *(*pa+5);
| Is This Answer Correct ? | 36 Yes | 3 No |
Answer / jaya prakash
Answer is D.
It is not a pointer to pointer.So we cannot use two stars.
| Is This Answer Correct ? | 6 Yes | 1 No |
The wrong answer is
d> *(*pa+5)
here value pointed to by pa is accessed and added 5 to it
then trying to print the value at that address, which gives
us an warning with some garbage value.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / vignesh1988i
d) is the wrong choice...... because , first variable pa
refers to a address of the array... * of that pa will give
you the first value of the array.. ie a[0] , then that value
will be getting added with 5 and the * which is outside wont
have any value towards this manuplation...... so this will
show an error...... illegal use of pointers.....
thank u
| Is This Answer Correct ? | 2 Yes | 0 No |
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