There are 9 coins. Out of which one is odd one i.e weight is
less or more. How many iterations of weighing are required
to find odd coin?
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Answer Posted / devendra singh
there are maximum two iterations in which the odd coin can
be found out
firstly weigh 3-3 coins and then there are two possibilities:
if they turn out two be equal that means the odd coin is in
the remaining 3 coins and then we can weigh any two coins
from the remaining 3 coins and if they are equal the left
one is odd and if they are not equal the one which is less
heavy or more heavier according to the problem will be the
odd one..
in the second condition if the 3-3 coins weighed earlier are
not equal then then the side of 3 coins which is heavier or
lighter as described in the problem will be taken and and
two coins from that will be weighed and as said earlier the
odd one can b spotted ...so just two weighings required.
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