Answer Posted / rajeshwar paste

Practically there is no formula, but u can refer various
cable supplier booklets in which they specify cable size
against current

Example

Conductor Requirements for ISO 10133 and ISO 13297
This appendix is reproduced from Annex 'A' (normative) of
both ISO 10133 and 13297. Both
ISOs are supporting Standards to the Recreational
Directive. The use of these recommendations
can be used to demonstrate compliance to this Directive.
Current Ratings
Table A1 gives allowable continuous current ratings in
amperes determined for an ambient
temperature of 30°C and the minimum number of strands for
conductors.
Table A1 - Conductor cross-sectional area, allowable
continuous current and stranding.
Maximum Current in amps for a single conductor at
insulation temperature ratings
Cross sectional
Area mm2
60°C 70°C 85 to 90°C 105°C 125°C 200°C
Minimum number of strands
Type A* Type B*
0.75 6 10 12 16 20 25 16
1 8 14 18 20 25 35 16
1.5 12 18 21 25 30 40 19 26
2.5 17 25 30 35 40 45 19 41
4 22 35 40 45 50 55 19 65
6 29 45 50 60 70 75 19 105
10 40 65 70 90 100 120 19 168
16 54 90 100 130 150 170 37 266
25 71 120 140 170 185 200 49 420
35 87 160 185 210 225 240 127 665
50 105 210 230 270 300 325 127 1064
70 135 265 285 330 360 375 127 1323
95 165 310 330 390 410 430 259 1666
120 190 360 400 450 480 520 418 2107
150 220 380 430 475 520 560 418 2107
NOTE: Conductor current ratings may be interpolated for
cross sectional areas between those shown in Table A1.
* Conductors with at least a Type A stranding shall be used
for general wiring of craft.
Conductors with Type B stranding shall be used for any
wiring where frequent flexing is involved
during use.
For conductors in engine rooms (60c
ambient), the maximum current rating in
tableA1 shall be de-rated by the factors:-
Temperature rating of conductor insulation °C Multiply
maximum current from table A1 by
70 0.75
85 to 90 0.82
105 0.86
125 0.89
200 1.0
BUNDLING (For a.c. only
When more than three a.c. conductors are bundled together
the maximum current ratings in
Table A1 shall be de-rated by the factor below:-
Number of conductors bundled Multiply maximum current from
A1 by
4 to

Define steady state error.

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My question is whether bellow formula is correct to find bus size for 46kA for 0.5 second & what is RT in bellow formula. formula to calculate the size of busbar to withstand the thermal stresses due to currents with duration of 0.2 sec to 5 sec. Sp = RT( I x I x t) / K Where Sp – is the cross sectional area of bus bar in millimeters. I -    is the value of AC fault current. t -    is the operating time of disconnecting device in seconds. K –  is the factor depending on the material of the conductor, insulation and initial and final temperature. Value of ‘k’ for copper is 143.

1463

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