fn name and variable name are same it get overloaded.. by changing the v

int zap(int n)
{
if(n<=1)then zap=1;
else zap=zap(n-3)+zap(n-1);
}
then the call zap(6) gives the values of zap
[a] 8 [b] 9 [c] 6 [d] 12 [e] 15

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Answer Posted / mazhar

fn name and variable name are same it get overloaded..

by changing the variable name the ans will be: 9

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