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Given an array of characters which form a sentence of
words, give an efficient algorithm to reverse the order of
the words (not characters) in it.
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Answer Posted / ashish
this works in O(n) as first reverse all the sentence....then
reverse each word....
#include<iostream.h>
#include<conio.h>
#include<string.h>
char a[50];
void wrd_reverse()
{
void str_rev(int start_index,int len);
int t=strlen(a);
str_rev(0,t);
int i=0;int st_indx=0;int count=0;
int size;
while(a[i]!='\0')
{
if(a[i]!=' ')
count++;
else
{
size=count;
str_rev(st_indx,size);
count=0;
st_indx=i+1;
}
i++;
}
size=count;
str_rev(st_indx,size);
}
void str_rev(int start_index,int len)
{
int sft=start_index;
int lenm=len/2;
len--;
for(int i=0;i<lenm;i++)
{
a[sft+i]=a[sft+i]+a[(sft+len)-i];
a[(sft+len)-i]=a[sft+i]-a[(sft+len)-i];
a[sft+i]=a[sft+i]-a[(sft+len)-i];
}
}
int main(){
cin.getline(a,40);
void wrd_reverse();
wrd_reverse();
cout.write(a,40);
return 0;
}
| Is This Answer Correct ? | 1 Yes | 2 No |
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