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What is the output of the program given below
#include<stdio.h>
main()
{
char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}
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Answer Posted / sharan
#include<stdio.h>
main()
{
char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}
Here the CATCH is semicolon after for
so maximum positive value for the signed char is 127.
Hence it loops 127 times after that value of i wraps to
negative value that is -128.
Thus it prints -128.
| Is This Answer Correct ? | 11 Yes | 1 No |
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