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what is the output of the following program?
#include<stdio.h>
void main()
{
float x=1.1;
while(x==1.1)
{
printf("\n%f",x);
x=x-0.1;
}
}
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Answer Posted / battini.laxman
No output.Loop will not execute atleast once. because
compiler will treat real constant as double. So real
constants will not store exactly equal to that constant
value but appproximately equal to that constan in binary
format. So float value and doule value storing
approximately equal but not exactly.small difference will
be there.so condition will fail at first time.So loop will
not execute atleast once.
| Is This Answer Correct ? | 17 Yes | 0 No |
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