Two MIT math graduates bump into each other at Fairway on
the upper west side. They hadn't seen each other in over 20
years.
The first grad says to the second: "how have you been?"
Second: "Great! I got married and I have three daughters
now"
First: "Really? how old are they?"
Second: "Well, the product of their ages is 72, and the sum
of their ages is the same as the number on that building
over there.."
First: "Right, ok.. oh wait.. hmmmm.., I still don't know"
second: "Oh sorry, the oldest one just started to play the
piano"
First: "Wonderful! my oldest is the same age!"
Problem: How old are the daughters?
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Answer Posted / helen
It's actually pretty simple...
The guy does not know the answer, if he knows only the sum &
product. he does know the answer if he knows the sum &
product & that the largest number is unique.
Therefore, there must be only one combination where the
largest number is unique, and one or more combinations where
the largest number is not unique. In other words, x^2 + y =
72, where x > y.
There is only one set of numbers that works: {6,6,2}.
Therefore, they are talking about Building 14.
So you need x+y+z=14, and x*y*z=2*2*2*3*3
We've made the leap of logic and it is just math from here.
| Is This Answer Correct ? | 6 Yes | 30 No |
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