struct point
{
int x;
int y;
};
struct point origin,*pp;
main()
{
pp=&origin;
printf("origin is(%d%d)\n",(*pp).x,(*pp).y);
printf("origin is (%d%d)\n",pp->x,pp->y);
}
Answer / susie
Answer :
origin is(0,0)
origin is(0,0)
Explanation:
pp is a pointer to structure. we can access the elements of
the structure either with arrow mark or with indirection
operator.
Note:
Since structure point is globally declared x & y are
initialized as zeroes
| Is This Answer Correct ? | 4 Yes | 0 No |
how to programme using switch statements and fuctions, a programme that will output two even numbers, two odd numbers and two prime numbers of the users chioce.
0 Answers Mbarara University of Science and Technology,
How can i find first 5 natural Numbers without using any loop in c language????????
main() { printf("\nab"); printf("\bsi"); printf("\rha"); }
Write a program to print a square of size 5 by using the character S.
3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.
void main() { static int i=5; if(--i){ main(); printf("%d ",i); } }
write a program for area of circumference of shapes
what will be the output of this program? void main() { int a[]={5,10,15}; int i=0,num; num=a[++i] + ++i +(++i); printf("%d",num); }
What are the following notations of defining functions known as? i. int abc(int a,float b) { /* some code */ } ii. int abc(a,b) int a; float b; { /* some code*/ }
#define a 10 int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } void foo() { #undef a #define a 50 }
Derive expression for converting RGB color parameters to HSV values
void main() { int i=10, j=2; int *ip= &i, *jp = &j; int k = *ip/*jp; printf(ā%dā,k); }