A man leaves office daily at 7pm. A driver with car comes
from his home to pick him from office and bring back home.
One day he gets free at 5:30 and instead of waiting for
driver he starts walking towards home. In the way he meets
the car and returns home on car He reaches home 20 minutes
earlier than usual. In how much time does the man reach home
usually?
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Answer / atul
Insufficient data.
That is why no one has posted the answer so far.
| Is This Answer Correct ? | 36 Yes | 21 No |
Answer / aditya
Since the car has met the person 20 minutes before hand, it has actually saved 10 mins of journey (to and fro)
since the man has started 1.30 hrs before and car has met him 10 mins before actual time he takes to reach daily is 1hr and 20 mins
| Is This Answer Correct ? | 12 Yes | 9 No |
Answer / rajesh
If Man reaches to his house befour 20 minutes by his usual time ,means he meet his vehicle befour 10 min of his usual time. The distance walk by him in 1:30hr is equal to distance cover by the vehicle in 10 min. hence 1:30-0:10= 1:20 mins........means he reach at home by the 8:30PM usually
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / ravi prakash
only ratio of car speed to man speed can be determined .
based on the data many we cant find out at what distance did car pick the vehicle,so multiple values are possible.
| Is This Answer Correct ? | 4 Yes | 6 No |
Answer / girish bhat
taxi cab leaves at 7pm.
he leaves at 5.30.
according to the ques he
reaches 20min early.Which
implies he reaches after
7pm.
so its 1hr30min - 20min =
1hr10min. this is the
closest logic i find in
this.
| Is This Answer Correct ? | 4 Yes | 7 No |
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