What is size of a object of following class?
class Foo
{
public:
void foo(){}
}
Answers were Sorted based on User's Feedback
Answer / sirama
Size of the Object 1 Byte (ie) 8 bits. Because that is
minimum possible size required to allocate something on
memory.
Say If a Create the Object like Foo obj;
Something needs to loaded on Stack. But, actually it does
not have any internal data memebers. Hence, the minimum
possible is 1 Byte.
Is This Answer Correct ? | 5 Yes | 0 No |
Answer / jitendra varshney
The size of the object here will be 1. Because by default,
if no variable is declared in the class the size of object is 1.
this is due to fact that when two or more object of the
class is defined then they would have the different
addresses. But if size would have been zero then it might be
possible that two or more object can have the same address.
Is This Answer Correct ? | 1 Yes | 1 No |
catch(exception &e) { . . . } Referring to the sample code above, which one of the following lines of code produces a written description of the type of exception that "e" refers to? a) cout << e.type(); b) cout << e.name(); c) cout << typeid(e).name(); d) cout << e.what(); e) cout << e;
what is static function
What is problem with overriding functions?
What is one dimensional array in c++?
What's c++ used for?
What is the protected keyword used for?
How do you flush a buffer in c++?
Explain overriding.
Differentiate between late binding and early binding. What are the advantages of early binding?
How to implement flags?
What does catch(…) mean?
Is C++ case sensitive a) False b) Depends on implementation c) True