what is the subnet for the host ip address 172.16.210.0/22
Answers were Sorted based on User's Feedback
Answer / jitendera kumar sinah
the given ip address is
172.16.210.0/22
scince it is class b address the it orignal mask should be 26 but given mask it 22 that is there is 6 bit of sunating
128+64+32+16+8+4=252
block size=256-252=4
now
210/4= 52
and remnder is 2(no matter)
that is
52*4=208
thus
subnet for the given host ip adress must be
172.16.208.0/22
thanks
Is This Answer Correct ? | 36 Yes | 11 No |
Answer / jitendera kumar sinah
the given ip address is
172.16.210.0/22
scince it is class b address the it orignal mask should be 16 but given mask it 22 that is there is 6 bit of sunating
128+64+32+16+8+4=252
block size=256-252=4
now
210/4= 52
and remnder is 2(no matter)
that is
52*4=208
thus
subnet for the given host ip adress must be
172.16.208.0/22
thanks
Is This Answer Correct ? | 14 Yes | 6 No |
Answer / jitendera sinha
i have done little typo mistake .in place of 16 i have written 26 in first answer.so i think on that basic i am wrong
Is This Answer Correct ? | 9 Yes | 3 No |
Answer / venkatesh i patil
no of subnet bits=6
no of subnets=2power6=64
no of host bits=10
no of valid hosts=(2power10)-2
increment=2power(no of host bits in interested octet)[here
interested octet is 3rd octet]=2power2=4
the multiple of 4 nearer to 210 is 208 so the subnet starts
with 172.16.208.0
subnet first valid host last valid host broadcast id
..16.208.0 172.16.209.0 172.16.210.0 172.16.211.0
172.16.208.0 is currect...
Is This Answer Correct ? | 7 Yes | 4 No |
Answer / efc
The address is a Class B = default subnet mask is 255.255.0.0
/22 = 255.255.252.0
increment = 4
multiple of 4 closest to 210 = 208
network is 172.16.208.0 /22
network address = 172.16.208.0
first valid host= 172.16.208.1
last valid host = 172.16.211.254
broadcast address= 172.16.211.255
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / anantharaman
this ll come under class B. so it has N:N:H:H. 2 network
portions and 2 host portions. 172.16.210.0/22 in dis qn /22
denotes de subnet n it means leaving de 2 octets n count
after tat.. i.e N(8):N(8):H(1+1+1+1+1+1):H(0)
8+8=16+1+1+1+1+1+1=22 so 128+64+32+16+8+4=252 the ans wud
be 255.255.252.0...
Is This Answer Correct ? | 3 Yes | 4 No |
Answer / s.m.feroz ahmed
Hi,
The Subnet for host ip address 172.16.210.0/22 is
255.255.0.0 as it belongs to classB.
Is This Answer Correct ? | 2 Yes | 8 No |
Answer / s.m.feroz ahmed
Hi,
255.255.0.0 is the Subnet for the host ip Address
172.16.210.0/22.
Is This Answer Correct ? | 0 Yes | 9 No |
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