what is the order of initialization for data?
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Answer / avi
Data members of a class are initialized in the order they
are declared in class. in case class is derived from some
base class then the base class will be initialized first
followed by the derived class.
| Is This Answer Correct ? | 14 Yes | 3 No |
Answer / sanjay makwana, puna
In order of class declared memeber variables.
| Is This Answer Correct ? | 11 Yes | 4 No |
Answer / nilay
all the static memebers are created at the time of class
definition and rest all non static memebers are created
when object is created of that class. member functions are
also create in memory when class is defined. (However only
single copy of static data members and functions is created)
| Is This Answer Correct ? | 7 Yes | 1 No |
Answer / vinay bondade
It is same as the order of declaration in the class.
| Is This Answer Correct ? | 14 Yes | 9 No |
Answer / kasi
1) Brief details on initialization:
To perform true initialization (not assignments) for a
class data member, C++ provides extened syntax for
constructor function.
Syntax:
class A
{
int ssn;
double sal;
public:
A(int j,double k):sal(k),ssn(j) //initialization
{
//assignement
}
}
Therefore constructor function has 2 parts they are
- initialization
- Assignment
Note - initialization will be excuted first and then
assignment
2) When is the initialization list mandatory?
- If the instance variable is constant
- If the class contains reference variable
3) coming to the posted question: order of member
initialization will be done in 2 ways by the compiler.
A) Declaration order
B) The order of members in the intialization list.
For the above example ssn is initialized first then sal.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / sachin magdum
Kasi, I am not agreed with you, in your case sal will be initialized before ssn.
Debug this program and see,
class A
{
int i ;
public :
A (int _i)
{
i = _i;
}
};
class B
{
A a;
A b;
A c;
public :
B(int _a, int _b, int _c) : a(_a), c(_c), b(_b)
{}
};
int main(int argc, char* argv[])
{
B b(1,2,3);
return 0;
}
Here the initialization order is first 'a' then 'c' and then 'b' and not a, b, c.
However, if you have base class then the case is little different
class A
{
int i ;
public :
A (int _i)
{
i = _i;
}
};
class B : public A
{
A a;
A b;
A c;
public :
B(int _a, int _b, int _c, int _base) : a(_a), c(_c), b(_b), A(_base)
{}
};
int main(int argc, char* argv[])
{
B b(1,2,3,4);
return 0;
}
In this case first 'A' that is base class of B, then 'a' then 'c' then 'b' will be initialized.
If you have multiple base classes, then they will be initialized in the order of their declaration, and not in the order how they are initialized.
class A
{
int i ;
public :
A (int _i)
{
i = _i;
}
};
class C
{
int i ;
public :
C (int _i)
{
i = _i;
}
};
class B : public A, public C
{
A a;
A b;
A c;
public :
B(int _a, int _b, int _c, int _baseA, int _baseC) : a(_a), C (_baseC), c(_c), b(_b), A(_baseA)
{}
};
int main(int argc, char* argv[])
{
B b(1,2,3,4,5);
return 0;
}
In this case first 'A' then 'C' then 'a' then 'c' and then 'b' will be initialized.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / g. maheshwari
The member and base classes are initialized in the order they appear in the class definition, not the order they appear in initialization list.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / karthik
there is no need for ordering a initialization of data.It
depends upon the program
| Is This Answer Correct ? | 4 Yes | 8 No |
Answer / mithali
I think initialization doesn't have any order.we r just
initializing the variables to some value.
| Is This Answer Correct ? | 6 Yes | 15 No |
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