Answer / mahesh-lanco

1 Ton capacity means---The cooling produced by melting of 1
ton of ice in a day is
taken as unit of refrigeration (in tons). Now unit of
refrigeration used in S.I. System is KW.
1 ton of refrigeration
= mass of ice x latent heat of ice / 24 hrs

= 900 kg x 335 KJ/Kg ( one short ton = 900 kgs )
------------------
24 x 3600 secs
= 3.4895 KJ/Sec
say 3.5 KJ / Sec = 3.5 KW

that is 1 ton of refrigeration = 3.5 KW


The amount of the heat required to convert 1 ton (2000
pounds)of ice in to water within 24 hours. The initial
temperature of water is 0 deg C.

Latent heat of ice= 144 BTU

1 TR= 144 X 2000
= 288000 BTU/24

For 1 hour

We can divid by 24 So 288000/24=12000BTU



1TR=12000BTU/Hr
=3024 K Cal/Hr
= 12600 K Jul/Hr
= 3.52 HW OR K Jul/Sec

Answer / rajeeva kunwar

The air conditioner capacity is measured in terms of Ton or
BTU (British Thermal Unit). BTU refers to the amount of
heat energy required to raise the temerature of 0.45 kg
water by 1 degree Fahrenheit. 1 ton AC is equivalent to
about 12,000 BTUs.

Answer / ghanshyam tiwari

Every thing has scale to measure such as cloth is measured
in meter and weight is measured in kg.so a.c. capacity is
measured in ton and 1 ton refers to "It is the amount of
heat required to melt 2000 pond of ice into water of 32
degree farnehight during a period of 24 hours."

Answer / jalaj

The air conditioner capacity is measured in terms of Ton or
BTU (British Thermal Unit). BTU refers to the amount of
heat energy required to raise the temerature of 0.45 kg
water by 1 degree Fahrenheit. 1 ton AC is equivalent to
about 12,000 BTUs.
1 Ton capacity means---The cooling produced by melting of 1
ton of ice in a day is
taken as unit of refrigeration (in tons). Now unit of
refrigeration used in S.I. System is KW.
1 ton of refrigeration
= mass of ice x latent heat of ice / 24 hrs
Every thing has scale to measure such as cloth is measured
in meter and weight is measured in kg.so a.c. capacity is
measured in ton and 1 ton refers to "It is the amount of
heat required to melt 2000 pond of ice into water of 32
degree farnehight during a period of 24 hours."

= 900 kg x 335 KJ/Kg ( one short ton = 900 kgs )
------------------
24 x 3600 secs
= 3.4895 KJ/Sec
say 3.5 KJ / Sec = 3.5 KW

that is 1 ton of refrigeration = 3.5 KW


The amount of the heat required to convert 1 ton (2000
pounds)of ice in to water within 24 hours. The initial
temperature of water is 0 deg C.

Latent heat of ice= 144 BTU

1 TR= 144 X 2000
= 288000 BTU/24

For 1 hour

We can divid by 24 So 288000/24=12000BTU



1TR=12000BTU/Hr
=3024 K Cal/Hr
= 12600 K Jul/Hr
= 3.52 HW OR K Jul/Sec

Please provide me detail cable voltage drop calculation

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