Answer / guest

132

Think of it this way: the first person shakes hands with 11
people, the second person also shakes hands with 11 people,
but you only count 10, because the hand shake with the first
person was already counted. Then add 9 for the third person,
8 for the fourth, & so on.

66 hand shakes took place before & 66 after the meeting, for
a total of 132.

Answer / ajay maurya

For n nuimber of persons shaking hands with each other,
total no of handshakes are n(n-1)/2.
Hence for 12 people itis 12(12-1)/2= 66
Thus total handshakes = 2*66=132

Answer / raj

For n nuimber of persons shaking hands with each other,
total no of handshakes are n(n-1)/2.
Hence for 12 people itis 12(12-1)/2= 66
Thus total handshakes = 2*66=132

Answer / vignesh1988i

132.........

thank u

Answer / saurabh sukhija

For n nuimber of persons shaking hands with each other,
total no of handshakes are n(n-1)
Thus total handshakes =12(12-1)=132

Answer / tharvesh

132 bcoz the total count is 12
Ans:n(n-1)
12(12-1)
12*11
132 is the Ans

Answer / rahul

At first time handshake will be 11 and decrease this to 1 that the formula of sum of this sereis is=n(n+1)/2.
that n=11 put in formula
(11*(11+1)/2)=66
66+66=132 bcoz handshake will be two times

Answer / maideen meeran

ans is 65handshake

u use any operation solve this problem 45-45=45

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