What is the four-digit number in which the first digit is
1/3 of the second, the third is the sum of the first and
second, and the last is three times the second?
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Answer / guest
The 4 digit number is 1349.
It is given that the first digit is 1/3 of the second. There
are 3 such possibilities.
1. 1 and 3
2. 2 and 6
3. 3 and 9
Now, the third digit is the sum of the first and second digits.
1. 1 + 3 = 4
2. 2 + 6 = 8
3. 3 + 9 = 12
It is clear that option 3 is not possible. So we are left
with only two options. Also, the last digit is three times
the second, which rules out the second option. Hence, the
answer is 1349.
Is This Answer Correct ? | 69 Yes | 2 No |
Answer / nessa
first=f,second=s,third=T,Last=L
f=s/3
T=f+s
L=3s
since s is divisible by 3,so s can be 3,6,9
Taking s=3
f=1
T=3+1=4
L=3*3=9
so answer is 1349
Is This Answer Correct ? | 5 Yes | 1 No |
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