three friends a,b,c run around a circular track of length
120m at a speed of 5,7,15m/sec respectively starting
simultaneously from the same point in the same
direction .how often they three will meet????
Answers were Sorted based on User's Feedback
Answer / thilak desingh
Guys, there can be two ways of interpreting,
1) How often they meet at any point
2) How often they meet at starting point
1) LCM { L/a-b , L/b-c} = 60 seconds
2) LCM { L/a , L/b , L/c } ~ 120 seconds
Is This Answer Correct ? | 3 Yes | 2 No |
Answer / manish pal
Soln: When two people are running in the same direction the relative speed is the difference in speeds of the two people.
In this case A=5 B=7 C=15
So relative speed of B wrt A is 7-5 = 3m/s
Relative speed of c wrt to a is 15-3 =15m/s
Therefore relative distances will be:
B wrt A is 120/2 =60
C wrt to A 120/12 =12
So they have to bridge this distance of 60 and 12 between them which is the LCM of 60 and 12 which is 60.
so ans is 60 sec
Is This Answer Correct ? | 4 Yes | 5 No |
Answer / nisha
Time taken by 'a' to cover a circular track = 120/5 = 24
seconds
Time taken by 'b' to cover a circular track = 120/7 seconds
Time taken by 'c' to cover a circular track = 120/15 = 8
seconds
LCM of 24, 8, 120/7 = 120/7seconds = ~ 17 seconds
So the three friends will meet after ~17 seconds
Is This Answer Correct ? | 6 Yes | 11 No |
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