In multilevel inheritance constructors will be executed
from the .... class to ... class
Answers were Sorted based on User's Feedback
Answer / ps
Constructors are always executed from the parent to child
ie in the example below:
#include <iostream>
using namespace std;
class base1
{
public:
base1()
{
cout<<"In constructor of base1"<<endl;
}
~base1()
{
cout<<"In destructor of base1"<<endl;
}
};
class base2:public base1
{
public:
base2()
{
cout<<"In constructor of base2"<<endl;
}
~base2()
{
cout<<"In destructor of base2"<<endl;
}
};
class derived :public base2
{
public:
derived()
{
cout<<"In constructor of derived"<<endl;
}
~derived()
{
cout<<"In destructor of derived"<<endl;
}
};
void main()
{
base1 b1;
base2 b2;
derived d1;
}
o/p:
In constructor of base1 --- for object b1
In constructor of base1 --- for object b2
In constructor of base2-----
In constructor of base1-for object d1
In constructor of base2
In constructor of derived
Is This Answer Correct ? | 19 Yes | 6 No |
Answer / chaitanya
In constructor of base1-----for object b1
In constructor of base1-----for object b2
In constructor of base2------for object b2
In constructor of base1-----for object d1
In constructor of base2-----for object d1
In constructor of derived----for object d1
In destructor of derived
In destructor of base2
In destructor of base1
Is This Answer Correct ? | 12 Yes | 6 No |
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