Answer / kashifhabib

Efficiency = (Output/Input)*100
&
Output (KW)= KVA * Power Factor
Input = Output + Iron losses + Copper losses
Iron losses are due to Primary voltage so remains constant
can be calculated by open circuit test
Copper losses are due to secondary current I*I*R
can be calculated by short circuit test
Exp: Full load copper losses 800 W
1/2 load copper losses will be 200 watts

Answer / vinod parasa

Efficiency = (Output/Input)*100
output=(x)(KVA * Power Factor)
input=(x)(KVA * Power Factor)+(X)^2 copperlosses+core losses

the volue of x depend on load
x=1 for full load
x=0.75 for (3/4)th load
x=0.5 for half load
x=0.25 for quarter load

copper losses are variable losses and iron losses are
constant losses.

at the time of full load copperlosses=iron losse
Full load copper losses 800 W
half load copper losses=(X)^2 copperlosses
x=0.5 for half load
=(0.5)^2 *400
=0.25*400
half load copper losses=200

Answer / n.makali

POWER Transformer is 55MVA, 27/11.5KV ,efficiency =99.49

Find the Losses of Transformer

Answer / s.ravi

Efficiency =
(Output/Output+Iron losses+Copper losses)*100
Iron losses = No load test,
Copper losses = Short circuit test
Regulation = (Impedance voltage/Rated input voltage)*100
Impedance voltage = Short circuit test(Voltage drop)

Answer / prof dr lehaz kakakhel

go for two tests
open and short circuits tests
From the open, u compute the core power loss and from the
short, u get copper losses. then the formula is
efficiency = output/ (output + the above two losses)
SIMPLE

Answer / ranag

repaired a 200 kva three phase distribution transformer his stander iron losses is 495 & copper losses is 3410 but the measured iron losses is 692 what formula is to know de-rated in kva ? pl answer with expal

hi everybody how to design string combiner box (scb) internal parameters like bus bar and spd (surge protection device and fuse which place to set that,and also bus bar one particular cross sectional how much heat generated and how much power loss tell me Clearly and briefly

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