sorry for not explaining it.
this is due to a concept of STACK which is a DATA STRUCTURE.
take the statement : printf("%d%d%d",i,++i,i++);
this list of variables will be getting stored in the stack. like the way shown:
i++
++i
i
since the operation of the stack is LIFO(last in first out)
the process will be done as said as LIFO but while retriving the data it will be printing according to the printf statement so only the output 3 3 1
Yes, but before giving the answer I wanna discuss the question.
In printf() function compiler calculates the values from
right to left (i.e. at first calculates the vale of i++,
then ++i and at last i)but prints the values from left to right.
So compiler at first calculates the value of i++, here i=1
so the value is printed 1 for i++, in the post increment the
value of i becomes 2, but in the pre increment which is ++i,
the value becomes 3, so the value is printed 3 for ++i, now
the value of i is 3, for this reason the value is printed
again 3 for i. But as I said before printf() function prints
from left to right
so the output will be 3 3 1
Given an int variable n that has been initialized to a
positive value and, in addition, int variables k and
total that have already been declared, use a do...while
loop to compute the sum of the cubes of the first n whole
numbers, and store this value in total . Thus if n equals
4, your code should put 1*1*1 + 2*2*2 + 3*3*3 + 4*4*4 into
total . Use no variables other than n , k , and total .
Given that two int variables, total and amount , have
been declared, write a sequence of statements that:
initializes total to 0
reads three values into amount , one at a time.
After each value is read in to amount , it is added to the
value in total (that is, total is incremented by the value
in amount ).
Instructor's notes: If you use a loop, it must be a for loop.
And if you use a loop control variable for counting, you
must declare it.
loop1:
{
x=i<n?(i++):0;
printf("%d",i);
exit(x);
continue;
}
Error- misplaced continue.
Doubt-1.will the exit(x) be executed for all values of x
2.will this statement go out of the program.
Given that two int variables, total and amount, have been
declared, write a loop that reads integers into amount and
adds all the non-negative values into total. The loop
terminates when a value less than 0 is read into amount.
Don't forget to initialize total to 0.
Instructor's notes: This problem requires either a while or
a do-while loop.
Given an int variable n that has already been declared and
initialized to a positive value, and another int variable
j that has already been declared, use a do...while loop to
print a single line consisting of n asterisks. Thus if n
contains 5, five asterisks will be printed. Use no variables
other than n and j .
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