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Categories  >>  Software  >>  Operating Systems  >>  RTOS  >>  Vxworks
 
 


 

 
 Vxworks interview questions  Vxworks Interview Questions
 Windows CE interview questions  Windows CE Interview Questions
 RTOS AllOther interview questions  RTOS AllOther Interview Questions
Question
Which RTOS supports Non-Preemptive scheduling ? Why other
scheduling methods are supported by such Oses?
 Question Submitted By :: SunitaKN
I also faced this Question!!     Rank Answer Posted By  
 
  Re: Which RTOS supports Non-Preemptive scheduling ? Why other scheduling methods are supported by such Oses?
Answer
# 1
The standard UNIX kernel is a nonpreemptive kernel; it does
not allow a user process to preempt a process executing in
kernel mode. Once a running process issues a system call and
enters kernel mode, preemptive context switches are disabled
until the system call is completed. Although there are
context switches, a system call may take an arbitrarily long
time to execute without voluntarily giving up the processor.
During that time, the process that made the system call may
delay the execution of a higher-priority, runnable, realtime
process.

The maximum process preemption latency for a nonpreemptive
kernel is the maximum amount of time it can take for the
running, kernel-mode process to switch out of kernel mode
back into user mode and then be preempted by a
higher-priority process. Under these conditions it is not
unusual for worst-case preemption to take seconds, which is
clearly unacceptable for many realtime applications.
 
Is This Answer Correct ?    14 Yes 8 No
SunitaKN
 

 
 
 
Other Vxworks Interview Questions
 
  Question Asked @ Answers
 
What is priority inversion? Juniper-Networks8
Which RTOS supports Non-Preemptive scheduling ? Why other scheduling methods are supported by such Oses? Elico1
IN RTOS HAVING 1OKBYTES OF MEMORY AND YOUR PROGRAMM FOR ASKING FOR 5KBYTES AND YOU GOT NULL ERROR ? WHY DOES IT BEHAVES LIKE THIS  3
I have a situation where the programme counter(PC) shows that vxworks msgQreceive function has been called by task A and Q is full, still I am not picking up the messages. There is no other task registered to receive messages from this Q. The sending task B, which is ISR in this case, is getting timedout everytime it tries posting new message in it. A's state is PEND which means I am waiting for some resource to get free but PC shows I have called vxworks msgQReceive and currently at qJobget+0x018 location. There seems to be two causes now(identified by me): either vxworks qjobget task is not able to do semTake or no messages in Q. But Q is full and semTake failure seems unlikely(though I dont have a mechanism to check so). Besides explaining root cause for above, can anyone suggest how to get my task in READY state again? I also tried flushing the Q; on doing this, more messages get posted in Q but A still doesnt pick up any :(  2
what do u mean by Semaphore..when v wil go for using this..explain about hat.what is the difference betw..binary ,,counting and mutex semphores Bosch1
What is another for creating a task without using taskspawn?  2
what are the various methods to overcome it?  2
 
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