In a colony there are some families. Each of them have
children but different in numbers.Following are conditions
a> no of adult>no of sons>no of daughters>no of families.
b>each sister must have atleast one brother and should
have
at the most
1 sister.
c> no of children in one family exceeds the sum of no of
children in the rest families
Tell the no of families
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No. of Families : 3
1st Family : 2 adult, 2 daughters, 3 sons
2nd Family : 2 adult, 2 daughters, 1 son
3rd Family : 2 adult, 1 son
Conditions :
a) no. of adults > no. of sons > no. of daughters > no. of
families
6 > 5 > 4 > 3
b) each sister must have atleast one brother and should have
at most 1 sister
in first family 1 sister had 3 bothers and 1 sister
c) no. of children in one family exceeds the sum of no. of
children in the rest families
1st family children > 2nd + 3rd family.
so the answer is 3.
| Is This Answer Correct ? | 25 Yes | 2 No |
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