Answer / abdur rab

The caller and callee are decoupled.

The caller doesn't know who the callee is; all it knows is
that there is a callee with a certain prototype and
probably some restriction (for instance, the returned value
can be int, but certain values have certain meanings).

This would be useful during the creation of libraries where
in you do not want the logic to be embedded in the library.

hele let us consider a function do_action exists in the
library. It takes three parameters (int, int, and a
function)

The do_action does not know what the passed function does.
#include <stdio.h>

int add ( int x, int y )
{
return ( x + y );
}

int sub ( int x, int y )
{
return ( x - y );
}

int mul ( int x, int y )
{
return ( x * y );
}

int div ( int x, int y )
{
return ( x / y );
}

int do_action ( int x, int y, int (*callback_function)
(int, int) )
{
return ( (*callback_function) ( x, y ) );
}

int main ( int argc, char* argv [] )
{
int x = 10;
int y = 2;

printf ("\nAdd %d", do_action ( x, y, &add ) );
printf ("\nSub %d", do_action ( x, y, &sub ) );
printf ("\nMul %d", do_action ( x, y, &mul ) );
printf ("\nDiv %d", do_action ( x, y, &div ) );

return ( 0 );
}

This is just an example. the usage of callback is more than
this

Answer / kapil sharma

callback function as the name suggest is basically a
function which gets called at the run time. it is a
reference to the executable code or a part of executable
code which is passed as an argument to another function.
for e.g if we want to forcefully terminate a program but if
there is some essential data which will get lost if program
gets terminated instantly.in that case writing a callback is
always a good deal.
---before writing a callback function you must have
knowledge of function pointers.

How do you view the path?

0 Answers  

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What is the output from this program? #include <stdio.h> void do_something(int *thisp, int that) { int the_other; the_other = 5; that = 2 + the_other; *thisp = the_other * that; } int main(void) { int first, second; first = 1; second = 2; do_something(&second, first); printf("%4d%4d\n", first, second); return 0; }

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