Source schema has nodes First Name, Last Name and
destination schema has node Name. How we can get data at
destination so that we can have two instance of Name
(without using orchestration).

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Source schema has nodes First Name, Last Name and destination schema has node Name. How we can get..

Answer / luigip

1) Build the map. The logic on how you get a single name is
not clear... Can be First Name concatenated with Last Name
(so simply use the string concatenate functoid adding a
space in between the fist and last name)
2) Create a receive port + Receive Location (name as RecLoc)
3) Create a send port
4) On the send port configure the map
5) On the send port add a filter where Receive Port Name is
equal to RecLoc

Is This Answer Correct ?    1 Yes 3 No

Source schema has nodes First Name, Last Name and destination schema has node Name. How we can get..

Answer / rajesh gorla

Ok, this is something like mapping flat source schema to
multiple occurrences of node in destination schema, use
Table Looping, Table Extractor functiond's and map. for
more info read this interesting article.

http://geekswithblogs.net/evankoch/archive/2007/08/07/114470
.aspx

Is This Answer Correct ?    3 Yes 6 No

Source schema has nodes First Name, Last Name and destination schema has node Name. How we can get..

Answer / sandeep

Create a MAP in Biz talk and add first name and last name
strings with space in between and map to destination schema
node. Use that map in port to port binding either in recieve
port or in send port.

Is This Answer Correct ?    6 Yes 11 No

Source schema has nodes First Name, Last Name and destination schema has node Name. How we can get..

Answer / navneet

Use the looping functoid to link FirstName and LastName to
Name. use this map as outbound map in send port binding.

Is This Answer Correct ?    2 Yes 10 No

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