Evaluate: int fn(int v) { if(v==1 || v==0) return 1; if(v%2==0)

Evaluate:
int fn(int v)
{
if(v==1 || v==0)
return 1;
if(v%2==0)
return fn(v/2)+2;
else
return fn(v-1)+3;
}
for fn(7);

a) 10
b) 11
c) 1

Question Posted / ramesh.chaluvadi

4 Answers
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Evaluate: int fn(int v) { if(v==1 || v==0) return 1; if(v%2==0) return fn(v/2)+2; ..

Answer / rajesh

Is This Answer Correct ?

8 Yes

1 No

Evaluate: int fn(int v) { if(v==1 || v==0) return 1; if(v%2==0) return fn(v/2)+2; ..

Answer / jagadish

The answer would be
b.

11 Its recursive function.so track for the returns
1st return:fn(v-1)+3;::v=7
2nd return fn(v/2)+2;::v=6
3rd return fn(v-1)+3;::v=3
4th return fn(v/2)+2;::v=2
5th return 1;::v=1

finally its 11=1+2+3+2+3

Is This Answer Correct ?

6 Yes

0 No

Evaluate: int fn(int v) { if(v==1 || v==0) return 1; if(v%2==0) return fn(v/2)+2; ..

Answer / babita sharma

The answer would be
b.

11 Its teh recursive function.

Is This Answer Correct ?

2 Yes

1 No

Evaluate: int fn(int v) { if(v==1 || v==0) return 1; if(v%2==0) return fn(v/2)+2; ..

Answer / jagdish patel

you have wrong option
correct answer is 9

solution:-
v=7;
so v is not =1,0 and also v%2 is not 0;
so (v-1)+3;
(7-1) + 3
6 + 3
= 9

Is This Answer Correct ?

3 Yes

8 No

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