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what is the purpose of _error_? : Sas programming


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More SAS Interview Questions

Mention the validation tools used in SAS?

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what the use of proc glm

1 Answers   Accenture, C Marc,


data data1; input dt account; format dt date9.; cards; 1745 1230 1756 1120 1788 1130 1767 1240 ; data data2; input startdt enddt total; format startdt date9. enddt date9.; cards; 1657 1834 12300 1557 1758 16800 1789 1789 12300 1788 1345 12383 1899 1899 13250 ; proc sql; create table data3 as select * from data1 as x left join data2 as y on x.dt>=y.startdt and x.dt<=y.enddt; quit; Here, we are getting cartision product. But,I want left join report consisting of this program. It should not get duplicate values. you can modify the program also.

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What are the difference between ceil and floor functions in sas?

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Describe the function and utility of the most difficult SAS macro that you have written?

0 Answers   Oracle,


Do you know the features of sas?

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How do dates work in sas?

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Explain data step in SAS

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I have a SCD Type 2 Dimention for Location In which A Sales Office in Having two Surrogate Keys just because of the change in it's Sales Group. SKey SalesGroup Sales Office BeginDate EndDate 280 SG1 SO1 01APR2000 01APR2010 281 SG2 SO1 02APR2010 31MAR2999 Now while loading the Fact, the Lookup ir returning SKey 280 for records before and after 01APR2010. I am not able to give WHERE condition in the Lookup Properties (TranDate between BeginDate and EndDate). Please help.

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What are the data types does SAS contain?

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Mention what is SAS data set?

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/* This is example of age caluculate wihtout to display perfect days and years in output window */ data age; retain dob "12jun2003"d now "24may2011"d; age1=now-dob; age=(now-dob)/365.25; years=int(age); days1=round((age-years)*365.25); months=month(now)-1; if days1 gt 30 and months in(12,10,8,6,4,2)then do; month1=days1/30.4375; month=int(days1/30.4375); if day(now)=1 then days=1; else days=round((month1-month)*30.4375)+1; drop days1 month1 month; end; else if days1 gt 30 and months in (1,3,5,7,9,11)then do; month1=days1/30.4375; month=int(days1/30.4375); if day(now)=1 then days=1; else days=round((month1-month) *30.4375); drop days1 month1 month; end; drop age age1; proc print data=age; format dob now date.; run;

1 Answers   Emerio,


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