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A wire of resistance 10 ohms is drawn out to three times its
original length. The new resistance will be
(1) 90 ohm
(2) 10 ohm
(3) 30 ohm
(4) 120 ohm
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Answer / harsh dubey
R=RHO*L/A
MULTIPLY AND DIVIDE BY L
R=RHO*L*L/A*L
AS RHO AND VOLUME(A*L)IS CONSTT.
SO
WE HAVE,
R2/R1=square of (L2/L1)
as increased by 3 times,putting L1=3L2
WE HAVE,
R2=9R1
OR
R2=square of (n)*r........
so correct answer is=90ohm
| Is This Answer Correct ? | 8 Yes | 2 No |
Answer / shwta
thnx a lot, mr harsh dubey! ur answer helped me a lot..
thanx again!! *gratitude*
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / p dilip kumar
As R= (SYMBOL ROW * L)/A
which means R is directly propotional to length
so when length of the wire is drawn three times obviously
the resistance will be multiple of 3.
Solution: 30 ohms
| Is This Answer Correct ? | 2 Yes | 9 No |
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