MASS TRANSFER - EXAMPLE 4.2 : In a non-dilute absorber, graphical method is used to represent the process. In an X - Y coordinate system, X-axis represents mole of carbon dioxide / mole of water and Y axis represents mole of carbon dioxide / mole of nitrogen. The inlet gas stream consists of 8 mol % of carbon dioxide in nitrogen. (a) Find the S / G minimum as a slope that goes through the point (0, 0.0304) and (0.0000488, 0.086957). (b) Find the actual slope of operating line when it is 1.5 times the S / G minimum! (c) Find the value of x for inlet gas stream when y = 1640 x, y is mole fraction of carbon dioxide in nitrogen.
MASS TRANSFER - ANSWER 4.2 : (a) S / G minimum = (0.086957 - 0.0304) / (0.0000488 - 0) = 1160. (b) S / G actual = 1.5 (1160) = 1740. (c) Let x = y / 1640 = 0.08 / 1640 = 0.0000487805. The value of y corresponds to 8 % or 0.08. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
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Which book I should refer for designing heat exchangers and reactors?
respected sir,i have been selected in the written examination prelim (CHEMICAL) of RINL(RASHTRIYE ISPAT NIGAM LTD.) held on 20 JUNE, So please tell me which type of questions will be asked in 2nd stage written exam. plz send me last 2-3 years questions asked in RINL(written exam).
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Heat transfer: In a triple effect evaporator, the heat transfer for an evaporator is calculated as q = UA (TI - TF) where TI is the initial temperature, TF is the final temperature; U and A are constants. Given that heat transfer for the first evaporator : q(1) = UA (TI - TB); second evaporator : q(2) = UA (TB - TC); third evaporator : q(3) = UA (TC - TF) where q(x) is the heat transfer function, TB is the temperature of second inlet and TC is the temperature of third inlet, prove that the overall heat transfer Q = q(1) q(2) q(3) = UA (TI - TF).
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