Answer / muzamil

if voltage regulator is single phage..in think its out put
I=kva*1000/230=65.21 amps...in full load,
if regulator 3 phage...I= kva*1000/415*1.732*pf*eff
=15*1000/415*1.732*.85*.85
=28 Amps.

Answer / rajkumar

we should convert that kva to kw,

Power (KW) =KVA*pf
           =15*0.8
     P  KW =12.
 then,
      P=1.732*V*I*COS*EFF
       
we need current,

      I=  P/1.732*V*COS*EFF
       =  12/1.732*415*0.8*80%
       =  17.7 A

Answer / deepanshu tiwari

for even 3-phase you don't divide "KVA" by p.f , so the current for 3 phase will be :
i= KVA/(1.713*line voltage)
i = (15 * 1000) / (1.713*line voltage(415V))
  = 21.10 A

without any theoretical calculations, can u approximately tell the current rating of a motor(above 30hp)working at 415VAC.

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