What is the code for following o/p
*
* *
* *
* *
* *
* *
* *
* *
*
Answer / unknown
#include<stdio.h>
void main()
{
int i,j,k,num = 5;
for(i = num;i > 0;i--){
for(j = 1;j <= i;j++){
printf(" ");
}
for(k = (j - 1);k < num;k++){
if(k==j-1 || k==num-1)
printf("*");
else
printf(" ");
printf(" ");
}
printf(" \n");
}
for(i = num;i > 0;i--){
for(j = (num - i);j > 0;j--){
printf(" ");
}
for(k = 0;k < i;k++){
if(k==0|| k==i-1)
printf("*");
else
printf(" ");
printf(" ");
}
printf(" \n");
}
}
Is This Answer Correct ? | 6 Yes | 1 No |
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