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public class Base {
public void myMethod(int a,intb) {}
}
// Uses myMethod and then hides it.
public class DerivedOne extends Base {
private void myMethod(int a,int b);
}
will this compile or not .yes or no. why
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Answer / ashwin khandelwal
It cannot be compiled because of weaker access privilege give to method in DerivedOne class while overidding method of Base Class
| Is This Answer Correct ? | 12 Yes | 0 No |
Answer / narayana
This will not compile because in the base class myMethod()
function is not having the body ,only abstract methods
should not have the body remaining all methods should have
the body
| Is This Answer Correct ? | 6 Yes | 6 No |
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class A{ m2(){ } } class B extends A{ m2(){ } } class c extends B{ m2(){ } } class my_class extends c{ m2(){ } pulic static void main(){ ...My_class a = new my_class(); super.super.super.m2(); is this is leagal if not find what is the legal procedure in order to call A's version of m2(); }
Core Java 
