Why LMTD is calculated in Heat -Exchanger problems..Why dont
we take average temperature??
Answers were Sorted based on User's Feedback
Answer / bharat
temperature inside heat-exchanger changes exponentially so
taking average would give erroneous results. and LMTD is
calculated by considering a small elemental area of heat
exchanger so it gives more accurate temperature difference.
Is This Answer Correct ? | 40 Yes | 3 No |
Answer / awkash
Because temperature change in heat exchanger is not linear
in nature so we can not take airthmatic mean here,
physically you can think in the manner like if we inlet
temp. of a pipe is 80 and outlet temp. is 40 then u cannot
say that temp in middle will be 60.
thats why for accurte measurement we take lmtd.
Is This Answer Correct ? | 4 Yes | 0 No |
Answer / abina
in heatexchanger temperature changes from point to point along the length so we are calculating Lmtd. ..Bt avg temperature dosnt gv correct value
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / anil
LMTD value it gives the correct average temperature without any errors compare to average temperature
Is This Answer Correct ? | 3 Yes | 16 No |
Question 75 - The molecular weights M in kg / mol of 3 different monomers a, b and c in a polymer are Ma = 14, Mb = 16 and Mc = 18. The fraction of polymer chain X of 3 different monomers a, b and c in a polymer are Xa = 0.5, Xb = 0.3 and Xc = 0.2. (i) Calculate number average molecular weight by using the formula Ma Xa + Mb Xb + Mc Xc. (ii) Calculate weight average molecular weight by using the formula (Ma Xa Ma + Mb Xb Mb + Mc Xc Mc) / (Ma Xa + Mb Xb + Mc Xc). (iii) Calculate the polydispersity by using the answer in (ii) divided by answer in (i). (iv) If the molecular weight of repeat unit is 12, calculate the degree of polymerization by using the formula (Ma Xa + Mb Xb + Mc Xc) / (molecular weight of repeat unit).
Hi, I am in need of interview questions from Engineers india limited in chemical engineering.if any one has kindly post it to me soon.
ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.12 : You, as an engineer, buy a piece of biochemical instrument to start a servicing business. The instrument has a useful life of 3 years, that costs $60k. The instrumental business generates $100k per year. The labor costs $50k per year. The $60k new instrument depreciates in its value evenly up to 3 years, thereafter the old instrument needs to be replaced by another piece of new instrument. (i) In the first year of this engineering business : (a) what is its starting cash? (b) calculate the depreciation value of the instrument. (c) find the operating profit generated. (d) what is the capital expense of the business? (e) calculate the cash from operation. (f) calculate the ending cash. (ii) Based on the income statement of the business in the second year : (a) find the capital expense of the business. (b) what is its starting cash? (c) calculate the depreciation value of the instrument. (d) find the operating profit generated. (e) calculate the cash from operation. (f) calculate the ending cash.
ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.34 : A biochemical engineering company has stock P = 20,000 shares of M % preferred stock of Q = $100 par and N number of shares of $20 par common stock. In year 1 : $10,000 is distributed as dividend. In year 2 : $25,000 is distributed as dividend. Let (Total Dividend) = (Dividend for Preferred Stock) + (Dividend for Common Stock). (a) In year 1, calculate the amount distributed as dividend for preferred stock, when no dividend was distributed for common stock. (b) In year 2, the amount distributed for common stock was $5000. Find the values of M and N, when the dividend per share for common stock is $0.05.
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