Answer / somasundarraj

1,2,3,4
2,3,4,5
.....
.....
37,38,39,40
and their reverse as
4,3,2,1
5,4,3,2
.....
....
40,39,38,37

total no. of ways to arrange 4 numbers out of 40 = 40 P 4

probability= 1- 12*37 / 40*39*38*37
= 29639 /29640

if the first 3 no.s are 1,3,8...so on (fibonacci series) den at which postion will you get 143?

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